If tan A = frac{1}{2}, then tan 3A = | vedclass

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(B) We know the formula for $	an 3A$ is given by: $	an 3A = \frac{3	an A - 	an^3 A}{1 - 3	an^2 A}$ Given $	an A = \frac{1}{2}$. Substituting the

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$\frac{11}{2}$

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(B) We know the formula for $	an 3A$ is given by: $	an 3A = \frac{3	an A - 	an^3 A}{1 - 3	an^2 A}$ Given $	an A = \frac{1}{2}$. Substituting the value of $	an A$ in the formula: $	an 3A = \frac{3(\frac{1}{2}) - (\frac{1}{2})^3}{1 - 3(\frac{1}{2})^2}$ $= \frac{\frac{3}{2} - \frac{1}{8}}{1 - 3(\frac{1}{4})}$ $= \frac{\frac{12 - 1}{8}}{1 - \frac{3}{4}}$ $= \frac{\frac{11}{8}}{\frac{4 - 3}{4}}$ $= \frac{11}{8} 	imes \frac{4}{1} = \frac{11}{2}$.

If $\tan A = \frac{1}{2},$ then $\tan 3A = $

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