જો A + B + C = 180^circ હોય,તો frac{sin 2A + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) આપેલ છે કે $A + B + C = 180^\circ.$અંશ $(N^r)$ = $\sin 2A + \sin 2B + \sin 2C = 4\sin A \sin B \sin C = 32\sin \frac{A}{2}\cos \frac{A}{2}\sin \fr

Vedclass · Accepted Answer

$8\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}$

Vedclass · Answer

(B) આપેલ છે કે $A + B + C = 180^\circ.$અંશ $(N^r)$ = $\sin 2A + \sin 2B + \sin 2C = 4\sin A \sin B \sin C = 32\sin \frac{A}{2}\cos \frac{A}{2}\sin \frac{B}{2}\cos \frac{B}{2}\sin \frac{C}{2}\cos \frac{C}{2}.$છેદ $(D^r)$ = $\cos A + \cos B + \cos C - 1 = 4\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}.$તેથી,$\frac{N^r}{D^r} = \frac{32\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}}{4\sin \frac{A}{2}\sin \frac{B}{2}\sin \frac{C}{2}} = 8\cos \frac{A}{2}\cos \frac{B}{2}\cos \frac{C}{2}.$

જો $A + B + C = 180^\circ$ હોય,તો $\frac{\sin 2A + \sin 2B + \sin 2C}{\cos A + \cos B + \cos C - 1} = $

Similar Questions

$\sin \frac{\pi }{14} \sin \frac{3\pi }{14} \sin \frac{5\pi }{14} \sin \frac{7\pi }{14} \sin \frac{9\pi }{14} \sin \frac{11\pi }{14} \sin \frac{13\pi }{14}$ નું મૂલ્ય કેટલું થાય?

$\frac{\cos ^{2} 45^{\circ}}{\sin ^{2} 60^{\circ}}+\frac{\cos ^{2} 60^{\circ}}{\sin ^{2} 45^{\circ}}-\frac{\tan ^{2} 30^{\circ}}{\cot ^{2} 45^{\circ}}-\frac{\sin ^{2} 30^{\circ}}{\cot ^{2} 30^{\circ}}$ નું સંખ્યાત્મક મૂલ્ય શોધો.

જો $A + B + C = 180^\circ$ હોય,તો $\sum \tan \frac{A}{2} \tan \frac{B}{2} = $

$3\cos \theta - 4\sin \theta $ ની મહત્તમ કિંમત કેટલી છે?

$\frac{(\tan 69^{\circ} + \tan 66^{\circ})}{(1 - \tan 69^{\circ} \tan 66^{\circ})}$ ની કિંમત શોધો.

Vedclass Test Series

Exam Paper Generator

Online Exam Module