If $\frac{3\pi}{4} < \alpha < \pi,$ then $\sqrt{\csc^2 \alpha + 2\cot \alpha}$ is equal to
- A$1 + \cot \alpha$
- B$1 - \cot \alpha$
- C$-1 - \cot \alpha$
- D$-1 + \cot \alpha$
Explore More
Similar Questions
The value of $\tan 57^{\circ} - \tan 12^{\circ} - \tan 57^{\circ} \tan 12^{\circ} =$ ?
Easy
View SolutionThe value of $\sin 10^\circ + \sin 20^\circ + \sin 30^\circ + ... + \sin 360^\circ$ is
Easy
View SolutionWhat is the value of $\frac{\sin A - 2 \sin^3 A}{2 \cos^3 A - \cos A}$?
Easy
View SolutionIf $\tan \theta = \frac{a}{b},$ then $\frac{{\sin \theta }}{{{{\cos }^8}\theta }} + \frac{{\cos \theta }}{{{{\sin }^8}\theta }} = $
Medium
View SolutionIf $\sin \theta + \cos \theta = \frac{17}{13}, 0 < \theta < 90^{\circ},$ then the value of $\sin \theta - \cos \theta$ is
Difficult
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo