If tan 80^{circ} = a and tan 47^{circ} = b,th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: $	an 80^{\circ} = a$ and $	an 47^{\circ} = b$.We know that $	an 80^{\circ} = \cot 10^{\circ} = \frac{1}{	an 10^{\circ}}$,therefore $	a

Vedclass · Accepted Answer

$\frac{ab - 1}{a + b}$

Vedclass · Answer

(C) Given: $	an 80^{\circ} = a$ and $	an 47^{\circ} = b$.We know that $	an 80^{\circ} = \cot 10^{\circ} = \frac{1}{	an 10^{\circ}}$,therefore $	an 10^{\circ} = \frac{1}{a}$.We need to find $	an 37^{\circ}$.We can write $	an 37^{\circ} = 	an(47^{\circ} - 10^{\circ})$.Using the formula $	an(A - B) = \frac{	an A - 	an B}{1 + 	an A 	an B}$,we get:$	an 37^{\circ} = \frac{	an 47^{\circ} - 	an 10^{\circ}}{1 + 	an 47^{\circ} 	an 10^{\circ}}$.Substituting the values,we have:$	an 37^{\circ} = \frac{b - \frac{1}{a}}{1 + b \cdot \frac{1}{a}}$.Multiplying the numerator and denominator by $a$,we get:$	an 37^{\circ} = \frac{ab - 1}{a + b}$.

If $\tan 80^{\circ} = a$ and $\tan 47^{\circ} = b$,then $\tan 37^{\circ}$ is equal to -

Similar Questions

If $A = \sin^8 \theta + \cos^{14} \theta$,then for all real values of $\theta$:

If $\alpha + \beta = \frac{\pi}{2}$ and $\beta + \gamma = \alpha$,then $\tan \alpha$ equals

If $\sin \theta = - \frac{1}{\sqrt{2}}$ and $\tan \theta = 1$,then $\theta$ lies in which quadrant?

The value of $\cot \frac{\pi}{20} \cot \frac{3 \pi}{20} \cot \frac{5 \pi}{20} \cot \frac{7 \pi}{20} \cot \frac{9 \pi}{20}$ is

If $\frac{{\sin^4 A}}{a} + \frac{{\cos^4 A}}{b} = \frac{1}{{a + b}},$ then the value of $\frac{{\sin^8 A}}{{a^3}} + \frac{{\cos^8 A}}{{b^3}}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module