If tan theta + cot theta = 2,then sin theta = | vedclass

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(B) Given the equation: $	an 	heta + \cot 	heta = 2$Since $\cot 	heta = \frac{1}{	an 	heta}$,we have: $	an 	heta + \frac{1}{	an 	heta} = 2$M

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$\frac{1}{\sqrt{2}}$

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(B) Given the equation: $	an 	heta + \cot 	heta = 2$Since $\cot 	heta = \frac{1}{	an 	heta}$,we have: $	an 	heta + \frac{1}{	an 	heta} = 2$Multiplying by $	an 	heta$: $	an^2 	heta + 1 = 2 	an 	heta$Rearranging the terms: $	an^2 	heta - 2 	an 	heta + 1 = 0$This is a perfect square: $(	an 	heta - 1)^2 = 0$Therefore,$	an 	heta = 1$Since $	an 	heta = 1$,$	heta = 45^\circ$ or $\frac{\pi}{4}$ radians.Now,calculate $\sin 	heta$: $\sin \frac{\pi}{4} = \frac{1}{\sqrt{2}}$.

If $\tan \theta + \cot \theta = 2$,then $\sin \theta =$

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