If x cos theta - sin theta = 1,then x^2 - (1 | vedclass

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(A) Given: $x \cos 	heta - \sin 	heta = 1$Rearranging the equation: $x \cos 	heta = 1 + \sin 	heta$Squaring both sides: $x^2 \cos^2 	heta = (1 +

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(A) Given: $x \cos 	heta - \sin 	heta = 1$Rearranging the equation: $x \cos 	heta = 1 + \sin 	heta$Squaring both sides: $x^2 \cos^2 	heta = (1 + \sin 	heta)^2$$x^2 (1 - \sin^2 	heta) = (1 + \sin 	heta)^2$$x^2 (1 - \sin 	heta)(1 + \sin 	heta) = (1 + \sin 	heta)^2$Since $1 + \sin 	heta 
eq 0$,we divide by $(1 + \sin 	heta)$:$x^2 (1 - \sin 	heta) = 1 + \sin 	heta$$x^2 - x^2 \sin 	heta = 1 + \sin 	heta$$x^2 - 1 = x^2 \sin 	heta + \sin 	heta$$x^2 - 1 = (1 + x^2) \sin 	heta$$x^2 - (1 + x^2) \sin 	heta = 1$

If $x \cos \theta - \sin \theta = 1$,then $x^2 - (1 + x^2) \sin \theta$ equals

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