If $2 \sin \left(\frac{\pi}{2}\right) = x^{2} + \frac{1}{x^{2}}$,then the value of $\left(x - \frac{1}{x}\right)$ is

  • A
    $-1$
  • B
    $2$
  • C
    $1$
  • D
    $0$

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