If A = {a, d}, B = {b, c, e} and C = {b, c, f | vedclass

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(A) Given sets are $A = \{a, d\}, B = \{b, c, e\}$ and $C = \{b, c, f\}$.First,calculate the set difference $(B - C)$:$(B - C) = \{b, c, e\} - \{b, c,

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$(A 	imes B) - (A 	imes C)$

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(A) Given sets are $A = \{a, d\}, B = \{b, c, e\}$ and $C = \{b, c, f\}$.First,calculate the set difference $(B - C)$:$(B - C) = \{b, c, e\} - \{b, c, f\} = \{e\}$.Now,find the Cartesian product $A 	imes (B - C)$:$A 	imes (B - C) = \{a, d\} 	imes \{e\} = \{(a, e), (d, e)\}$.Next,calculate $(A 	imes B) - (A 	imes C)$:$A 	imes B = \{(a, b), (a, c), (a, e), (d, b), (d, c), (d, e)\}$.$A 	imes C = \{(a, b), (a, c), (a, f), (d, b), (d, c), (d, f)\}$.$(A 	imes B) - (A 	imes C) = \{(a, e), (d, e)\}$.Since both results are equal,$A 	imes (B - C) = (A 	imes B) - (A 	imes C)$.

If $A = \{a, d\}, B = \{b, c, e\}$ and $C = \{b, c, f\},$ then $A \times (B - C) =$

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