If x=3 and y=4, then find the value of 256 x^ | vedclass

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(B) The given expression is $256 x^{4}+160 x^{2} y^{2}+25 y^{4}$.This can be written in the form of $(a+b)^{2} = a^{2} + 2ab + b^{2}$.$256 x^{4}+160 x

Vedclass · Accepted Answer

$50176$

Vedclass · Answer

(B) The given expression is $256 x^{4}+160 x^{2} y^{2}+25 y^{4}$.This can be written in the form of $(a+b)^{2} = a^{2} + 2ab + b^{2}$.$256 x^{4}+160 x^{2} y^{2}+25 y^{4} = (16 x^{2})^{2} + 2(16 x^{2})(5 y^{2}) + (5 y^{2})^{2}$.This simplifies to $(16 x^{2} + 5 y^{2})^{2}$.Now,substitute $x=3$ and $y=4$ into the expression:$(16(3)^{2} + 5(4)^{2})^{2} = (16 	imes 9 + 5 	imes 16)^{2}$.$= (144 + 80)^{2} = (224)^{2}$.$(224)^{2} = 50176$.

If $x=3$ and $y=4,$ then find the value of $256 x^{4}+160 x^{2} y^{2}+25 y^{4}$.

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