If log _{10} 5 + log _{10}(5x + 1) = log _{10 | vedclass

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(B) Given equation: $\log _{10} 5 + \log _{10}(5x + 1) = \log _{10}(x + 5) + 1$Using the property $\log a + \log b = \log(ab)$,we get:$\log _{10}[5(5x

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$3$

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(B) Given equation: $\log _{10} 5 + \log _{10}(5x + 1) = \log _{10}(x + 5) + 1$Using the property $\log a + \log b = \log(ab)$,we get:$\log _{10}[5(5x + 1)] = \log _{10}(x + 5) + \log _{10} 10$ (since $\log _{10} 10 = 1$)$\log _{10}[5(5x + 1)] = \log _{10}[10(x + 5)]$Removing the logarithms from both sides:$5(5x + 1) = 10(x + 5)$$25x + 5 = 10x + 50$$25x - 10x = 50 - 5$$15x = 45$$x = 3$

If $\log _{10} 5 + \log _{10}(5x + 1) = \log _{10}(x + 5) + 1$,then $x$ is equal to

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