If 2 sin^{2} theta - cos^{2} theta = 2,then f | vedclass

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(B) Given equation: $2 \sin^{2} 	heta - \cos^{2} 	heta = 2$Using the identity $\cos^{2} 	heta = 1 - \sin^{2} 	heta$,we substitute it into the equa

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(B) Given equation: $2 \sin^{2} 	heta - \cos^{2} 	heta = 2$Using the identity $\cos^{2} 	heta = 1 - \sin^{2} 	heta$,we substitute it into the equation:$2 \sin^{2} 	heta - (1 - \sin^{2} 	heta) = 2$Simplify the expression:$2 \sin^{2} 	heta - 1 + \sin^{2} 	heta = 2$$3 \sin^{2} 	heta - 1 = 2$Add $1$ to both sides:$3 \sin^{2} 	heta = 3$Divide by $3$:$\sin^{2} 	heta = 1$Taking the square root:$\sin 	heta = 1$ (considering the principal value)Since $\sin 90^{\circ} = 1$,we have:$	heta = 90^{\circ}$

If $2 \sin^{2} \theta - \cos^{2} \theta = 2$,then find the value of $\theta$. (in $^{\circ}$)

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