If 49 x^{2}-b=left(7 x+frac{1}{2}right)left(7 | vedclass

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Question

(A) Given the equation: $49 x^{2}-b=\left(7 x+\frac{1}{2}\right)\left(7 x-\frac{1}{2}\right)$Using the algebraic identity $(a+b)(a-b)=a^{2}-b^{2}$,whe

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(A) Given the equation: $49 x^{2}-b=\left(7 x+\frac{1}{2}\right)\left(7 x-\frac{1}{2}\right)$Using the algebraic identity $(a+b)(a-b)=a^{2}-b^{2}$,where $a=7x$ and $b=\frac{1}{2}$,we have:$49 x^{2}-b=(7 x)^{2}-\left(\frac{1}{2}\right)^{2}$$49 x^{2}-b=49 x^{2}-\frac{1}{4}$Comparing both sides of the equation,we find that $b=\frac{1}{4}$.Therefore,the correct option is $A$.

If $49 x^{2}-b=\left(7 x+\frac{1}{2}\right)\left(7 x-\frac{1}{2}\right),$ then the value of $b$ is

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