If p(x) = x^2 - 4x + 3,evaluate: p(2) - p(-1) | vedclass

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(D) Given the polynomial $p(x) = x^2 - 4x + 3$.First,calculate $p(2)$:$p(2) = (2)^2 - 4(2) + 3 = 4 - 8 + 3 = -1$.Next,calculate $p(-1)$:$p(-1) = (-1)^

Vedclass · Accepted Answer

$\frac{-31}{4}$

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(D) Given the polynomial $p(x) = x^2 - 4x + 3$.First,calculate $p(2)$:$p(2) = (2)^2 - 4(2) + 3 = 4 - 8 + 3 = -1$.Next,calculate $p(-1)$:$p(-1) = (-1)^2 - 4(-1) + 3 = 1 + 4 + 3 = 8$.Then,calculate $p\left(\frac{1}{2}\right)$:$p\left(\frac{1}{2}\right) = \left(\frac{1}{2}\right)^2 - 4\left(\frac{1}{2}\right) + 3 = \frac{1}{4} - 2 + 3 = \frac{1}{4} + 1 = \frac{5}{4}$.Finally,evaluate the expression $p(2) - p(-1) + p\left(\frac{1}{2}\right)$:$= -1 - 8 + \frac{5}{4} = -9 + \frac{5}{4} = \frac{-36 + 5}{4} = \frac{-31}{4}$.

If $p(x) = x^2 - 4x + 3$,evaluate: $p(2) - p(-1) + p\left(\frac{1}{2}\right)$

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