If frac{5}{x}-frac{4}{y}=4 and frac{4}{x}-fra | vedclass

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(D) Given equations are:$(1)$ $\frac{5}{x} - \frac{4}{y} = 4$$(2)$ $\frac{4}{x} - \frac{5}{y} = 5$Subtracting equation $(2)$ from equation $(1)$:$(\fr

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(D) Given equations are:$(1)$ $\frac{5}{x} - \frac{4}{y} = 4$$(2)$ $\frac{4}{x} - \frac{5}{y} = 5$Subtracting equation $(2)$ from equation $(1)$:$(\frac{5}{x} - \frac{4}{y}) - (\frac{4}{x} - \frac{5}{y}) = 4 - 5$$\frac{5}{x} - \frac{4}{y} - \frac{4}{x} + \frac{5}{y} = -1$$(\frac{5}{x} - \frac{4}{x}) + (\frac{5}{y} - \frac{4}{y}) = -1$$\frac{1}{x} + \frac{1}{y} = -1$ (This is not the required form).Let us add the two equations:$(\frac{5}{x} - \frac{4}{y}) + (\frac{4}{x} - \frac{5}{y}) = 4 + 5$$\frac{9}{x} - \frac{9}{y} = 9$Dividing the entire equation by $9$:$\frac{1}{x} - \frac{1}{y} = 1$

If $\frac{5}{x}-\frac{4}{y}=4$ and $\frac{4}{x}-\frac{5}{y}=5,$ then $\frac{1}{x}-\frac{1}{y}=\ldots \ldots \ldots \ldots .(x, y \neq 0)$

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