If Z = 36.8 and M = 33.6,then bar{x} = ldots | vedclass

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(C) The empirical relationship between Mean $(\bar{x})$,Median $(M)$,and Mode $(Z)$ is given by the formula:$Z = 3M - 2\bar{x}$Given values are $Z = 3

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(C) The empirical relationship between Mean $(\bar{x})$,Median $(M)$,and Mode $(Z)$ is given by the formula:$Z = 3M - 2\bar{x}$Given values are $Z = 36.8$ and $M = 33.6$.Substituting these values into the formula:$36.8 = 3(33.6) - 2\bar{x}$Calculate $3 	imes 33.6$:$36.8 = 100.8 - 2\bar{x}$Rearrange the equation to solve for $\bar{x}$:$2\bar{x} = 100.8 - 36.8$$2\bar{x} = 64$Divide by $2$:$\bar{x} = \frac{64}{2} = 32$Thus,the value of $\bar{x}$ is $32$.

Class interval	$10-25$	$25-40$	$40-55$	$55-70$	$70-85$	$85-100$
Number of students	$2$	$3$	$7$	$6$	$6$	$6$

Class	$0-30$	$30-60$	$60-90$	$90-120$	$120-150$	$150-180$
Frequency	$8$	$15$	$16$	$20$	$12$	$9$

If $Z = 36.8$ and $M = 33.6$,then $\bar{x} = \ldots \ldots \ldots \ldots .$

Similar Questions

The marks distribution of $30$ students in a mathematics examination is given in the table. Find the mode of this data. Also,compare and interpret the mode and the mean.
Class interval $10-25$ $25-40$ $40-55$ $55-70$ $70-85$ $85-100$
Number of students $2$ $3$ $7$ $6$ $6$ $6$

The formula $\ldots \ldots$ represents the empirical relationship between the measures of central tendency.

If $Z+M=34$ and $M+\bar{x}=40,$ then $M=\ldots \ldots \ldots . . .$

Find the mean,median,and mode of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$

Frequency $5$ $27$ $58$ $20$ $10$

Find the mean,median and mode of the following frequency distribution:

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Frequency $8$ $15$ $16$ $20$ $12$ $9$

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