If $A$ and $B$ are any two sets,then $(A \cap B)'$ is equal to

For the two events $A$ and $B$,$P(A) = 0.38$ and $P(B) = 0.41$. Find the value of $P(\text{not } A)$.

Taking the set of natural numbers as the universal set,write down the complement of the following set:
$A = \{ x : x \text{ is an even natural number} \}$

Let $U = \{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 \}$,$A = \{ 1, 2, 5 \}$,and $B = \{ 6, 7 \}$. Then $A \cap B'$ is:

Taking the set of natural numbers as the universal set,write down the complements of the following sets:
$A = \{ x : x \text{ is a perfect cube} \}$

Given $n(U) = 20$,$n(A) = 12$,$n(B) = 9$,$n(A \cap B) = 4$,where $U$ is the universal set,$A$ and $B$ are subsets of $U$,then $n((A \cup B)^C) = $