Taking the set of natural numbers as the universal set,write down the complements of the following sets:
$A = \{ x : x \text{ is a perfect cube} \}$
$A = \{ x : x \text{ is a perfect cube} \}$
- A$A' = \{ x : x \in N \text{ and } x \text{ is not a perfect cube} \}$
- B$A' = \{ x : x \in N \text{ and } x \text{ is a perfect square} \}$
- C$A' = \{ x : x \in N \text{ and } x \text{ is an even number} \}$
- D$A' = \{ x : x \in N \text{ and } x \text{ is an odd number} \}$
Explore More
Similar Questions
If $U = \{a, b, c, d, e, f, g, h\}$,find the complement of the set $C = \{a, c, e, g\}$.
Easy
View Solution$A$ and $B$ are events such that $P(A)=0.42$,$P(B)=0.48$ and $P(A \cap B)=0.16$. Determine $P(\text{not } A)$.
Easy
View SolutionTaking the set of natural numbers as the universal set,write down the complement of the following set:
$A = \{ x: x \ge 7 \}$
$A = \{ x: x \ge 7 \}$
Easy
View SolutionGiven $n(U) = 20$,$n(A) = 12$,$n(B) = 9$,$n(A \cap B) = 4$,where $U$ is the universal set,$A$ and $B$ are subsets of $U$,then $n((A \cup B)^C) = $
Easy
View SolutionTaking the set of natural numbers as the universal set,write down the complement of the following set:
$A = \{ x : x \in N \text{ and } 2x + 1 > 10 \}$
$A = \{ x : x \in N \text{ and } 2x + 1 > 10 \}$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo