If $HCF(a, b) = 12$,then which of the following cannot be the $LCM(a, b)$? Options: $(A) 90, (B) 24, (C) 48, (D) 60$.

  • A
    $90$
  • B
    $24$
  • C
    $48$
  • D
    $60$

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If $\text{g.c.d.}(336, 52) = 4$,then $\text{l.c.m.}(336, 52) = \dots$

Find the $g.c.d.$ of $240$ and $6552$ using Euclid's division algorithm.

The smallest positive number divisible by every integer from $2$ to $10$ is:

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The $\text{l.c.m.}$ of two numbers is $14$ times their $\text{g.c.d.}$ and the sum of $\text{l.c.m.}$ and $\text{g.c.d.}$ is $600$. If one of the numbers is $280$,then find the other number.

$L.C.M.(115, 25) = \ldots$

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