If x = 2^{1/3} - 2^{-1/3},then 2x^3 + 6x = | vedclass

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(C) Given $x = 2^{1/3} - 2^{-1/3}$.Cubing both sides,we get:$x^3 = (2^{1/3} - 2^{-1/3})^3$Using the identity $(a - b)^3 = a^3 - b^3 - 3ab(a - b)$:$x^3

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$3$

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(C) Given $x = 2^{1/3} - 2^{-1/3}$.Cubing both sides,we get:$x^3 = (2^{1/3} - 2^{-1/3})^3$Using the identity $(a - b)^3 = a^3 - b^3 - 3ab(a - b)$:$x^3 = (2^{1/3})^3 - (2^{-1/3})^3 - 3(2^{1/3})(2^{-1/3})(2^{1/3} - 2^{-1/3})$$x^3 = 2 - 2^{-1} - 3(1)(x)$$x^3 = 2 - \frac{1}{2} - 3x$$x^3 = \frac{3}{2} - 3x$Multiplying by $2$:$2x^3 = 3 - 6x$$2x^3 + 6x = 3$.

If $x = 2^{1/3} - 2^{-1/3}$,then $2x^3 + 6x = $

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