If z = 1 - cos alpha + i sin alpha ,then text | vedclass

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(D) Given $z = 1 - \cos \alpha + i \sin \alpha$. Using trigonometric identities $1 - \cos \alpha = 2 \sin^2 \frac{\alpha}{2}$ and $\sin \alpha = 2 \si

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$\frac{\pi}{2} - \frac{\alpha}{2}$

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(D) Given $z = 1 - \cos \alpha + i \sin \alpha$. Using trigonometric identities $1 - \cos \alpha = 2 \sin^2 \frac{\alpha}{2}$ and $\sin \alpha = 2 \sin \frac{\alpha}{2} \cos \frac{\alpha}{2}$. $z = 2 \sin^2 \frac{\alpha}{2} + i (2 \sin \frac{\alpha}{2} \cos \frac{\alpha}{2}) = 2 \sin \frac{\alpha}{2} (\sin \frac{\alpha}{2} + i \cos \frac{\alpha}{2})$. Since $\sin \frac{\alpha}{2} + i \cos \frac{\alpha}{2} = \cos(\frac{\pi}{2} - \frac{\alpha}{2}) + i \sin(\frac{\pi}{2} - \frac{\alpha}{2})$. Thus,$	ext{amp } z = \frac{\pi}{2} - \frac{\alpha}{2}$.

If $z = 1 - \cos \alpha + i \sin \alpha $,then $\text{amp } z$ =

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