If $f(x) = \frac{2^x}{2^x + \sqrt{2}}$,$x \in R$,then $\sum_{k=1}^{81} f\left(\frac{k}{82}\right)$ is equal to :

  • A
    $41$
  • B
    $\frac{81}{2}$
  • C
    $82$
  • D
    $81 \sqrt{2}$

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