If $10 \sin^4 \theta + 15 \cos^4 \theta = 6$,then the value of $\frac{27 \operatorname{cosec}^6 \theta + 8 \sec^6 \theta}{16 \sec^8 \theta}$ is:

  • A
    $\frac{2}{5}$
  • B
    $\frac{3}{4}$
  • C
    $\frac{3}{5}$
  • D
    $\frac{1}{5}$

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