If b + c, c + a, a + b are in H.P.,then frac{ | vedclass

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(A) Given that $b + c, c + a, a + b$ are in $H.P.$This implies that their reciprocals $\frac{1}{b + c}, \frac{1}{c + a}, \frac{1}{a + b}$ are in $A.P.

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$A.P.$

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(A) Given that $b + c, c + a, a + b$ are in $H.P.$This implies that their reciprocals $\frac{1}{b + c}, \frac{1}{c + a}, \frac{1}{a + b}$ are in $A.P.$Let $S = a + b + c$. Multiplying each term by $S$,we get $\frac{a + b + c}{b + c}, \frac{a + b + c}{c + a}, \frac{a + b + c}{a + b}$ are in $A.P.$This can be written as $\frac{a}{b + c} + 1, \frac{b}{c + a} + 1, \frac{c}{a + b} + 1$ are in $A.P.$Subtracting $1$ from each term,we get $\frac{a}{b + c}, \frac{b}{c + a}, \frac{c}{a + b}$ are in $A.P.$

If $b + c, c + a, a + b$ are in $H.P.$,then $\frac{a}{b + c}, \frac{b}{c + a}, \frac{c}{a + b}$ are in

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