(A) Given the quadratic expression $f(x) = x^2 - 6x + 10$. We can rewrite this by completing the square: $f(x) = (x^2 - 6x + 9) + 1$ $f(x) = (x - 3)^2

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(A) Given the quadratic expression $f(x) = x^2 - 6x + 10$. We can rewrite this by completing the square: $f(x) = (x^2 - 6x + 9) + 1$ $f(x) = (x - 3)^2 + 1$. Since $(x - 3)^2 \ge 0$ for all real $x$,the minimum value of $(x - 3)^2$ is $0$ when $x = 3$. Therefore,the least value of $f(x)$ is $0 + 1 = 1$.

Class 11 Mathematics 2 Complex Numbers and Quadratic Equations: Quadratic Equations Quadratic expressions and Position of roots

Easy

If $x$ is real,the least value of $x^2 - 6x + 10$ is

A
$1$
B
$2$
C
$3$
D
$10$

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2 Complex Numbers and Quadratic Equations: Quadratic Equations

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Quadratic expressions and Position of roots

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If $x$ is real,the least value of $x^2 - 6x + 10$ is

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All the values of $k$ such that the quadratic expression $2kx^2 - (4k+1)x + 2$ is negative for exactly three integral values of $x$,lie in the interval

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