If $\int_0^{\frac{\pi}{2}} \log \cos x \, dx = \frac{\pi}{2} \log \left(\frac{1}{2}\right)$,then $\int_0^{\frac{\pi}{2}} \log \sec x \, dx = $

  • A
    $\frac{\pi}{2} \log \left(\frac{1}{2}\right)$
  • B
    $1 - \frac{\pi}{2} \log \left(\frac{1}{2}\right)$
  • C
    $1 + \frac{\pi}{2} \log \left(\frac{1}{2}\right)$
  • D
    $\frac{\pi}{2} \log 2$

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