If $y = (\tan^{-1} x)^2$,then $(x^2 + 1)^2 \frac{d^2 y}{dx^2} + 2x(x^2 + 1) \frac{dy}{dx} = $

  • A
    $4$
  • B
    $2$
  • C
    $1$
  • D
    $0$

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