જો $u = \frac{\tan^{-1} x}{\tan^{-1} x + 1}$ અને $v = \tan^{-1}(\tan^{-1} x)$ હોય,તો $\frac{du}{dv} = \dots$

  • A
    $1$
  • B
    $\frac{1 + (\tan^{-1} x)^2}{(1 + \tan^{-1} x)^2}$
  • C
    $\frac{\tan^{-1} x}{(1 + \tan^{-1} x)^2}$
  • D
    $\frac{1}{(1 + \tan^{-1} x)^2}$

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