If (p wedge sim r) rightarrow (sim p vee q) h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The implication $A \rightarrow B$ is $False$ only when $A$ is $True$ and $B$ is $False$.Given $(p \wedge \sim r) \rightarrow (\sim p \vee q) \equi

Vedclass · Accepted Answer

$T, F, F$

Vedclass · Answer

(C) The implication $A \rightarrow B$ is $False$ only when $A$ is $True$ and $B$ is $False$.Given $(p \wedge \sim r) \rightarrow (\sim p \vee q) \equiv F$.This implies $(p \wedge \sim r) \equiv T$ and $(\sim p \vee q) \equiv F$.From $(\sim p \vee q) \equiv F$,we get $\sim p \equiv F$ and $q \equiv F$,which means $p \equiv T$ and $q \equiv F$.Substituting $p \equiv T$ into $(p \wedge \sim r) \equiv T$,we get $(T \wedge \sim r) \equiv T$,which implies $\sim r \equiv T$,so $r \equiv F$.Thus,the truth values are $p=T, q=F, r=F$.Therefore,Option $(C)$ is correct.

If $(p \wedge \sim r) \rightarrow (\sim p \vee q)$ has a truth value of $False$,then the truth values of $p, q, r$ are respectively:

Similar Questions

The logical statement $[\sim(\sim p \vee q) \vee (p \wedge r) \wedge (\sim q \wedge r)]$ is equivalent to

The negation of $(p \wedge \sim q) \rightarrow (p \vee \sim q)$ is

Identify the type of "Or" used in the following statement and check whether the statement is true or false:
$\sqrt{2}$ is a rational number or an irrational number.

Simplify the following switching circuit and find the corresponding Boolean expression.

The inverse of the statement pattern $(p \vee q) \rightarrow (p \wedge q)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module