If 3 books on Physics,2 books on Chemistry,an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) There are $3$ books on Physics,$2$ books on Chemistry,and $4$ books on Mathematics. Since all Physics books must be together,we treat them as $1$

Vedclass · Accepted Answer

$3456$

Vedclass · Answer

(C) There are $3$ books on Physics,$2$ books on Chemistry,and $4$ books on Mathematics. Since all Physics books must be together,we treat them as $1$ unit. Since all Mathematics books must be together,we treat them as $1$ unit. There are $2$ individual Chemistry books. Thus,we have $1$ (Physics unit) + $1$ (Mathematics unit) + $2$ (Chemistry books) = $4$ units to arrange. These $4$ units can be arranged in $4!$ ways. The $3$ Physics books can be arranged among themselves in $3!$ ways. The $4$ Mathematics books can be arranged among themselves in $4!$ ways. $	herefore 	ext{Total arrangements} = 4! 	imes 3! 	imes 4! = 24 	imes 6 	imes 24 = 3456$.

If $3$ books on Physics,$2$ books on Chemistry,and $4$ books on Mathematics are to be arranged on a shelf so that all the Physics books are together and all the Mathematics books are together,then the number of such arrangements is

Similar Questions

How many numbers lying between $500$ and $600$ can be formed with the help of the digits $1, 2, 3, 4, 5, 6$ when the digits are not to be repeated?

There are $10$ distinct letters of the English alphabet. Words of $5$ letters are formed using these letters. How many such words can be formed if at least one letter is repeated?

If all the letters of the word $MOST$ are permuted and the words (with or without meaning) thus obtained are arranged in the dictionary order,then the rank of the word $STOM$ when counted from the rank of the word $MOST$ is:

How many words,with or without meaning,can be formed using all the letters of the word $EQUATION$,using each letter exactly once?

${ }^{15} P_8 = A + 8 \cdot { }^{14} P_7 \Rightarrow A = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module