If $A$ and $B$ are independent events and $P(A)=\frac{2}{3}$ and $P(B)=\frac{3}{5}$,then $P(A^{\prime} \cap B)$ is equal to:

In a box of $10$ electric bulbs,two are defective. Two bulbs are selected at random one after the other from the box. The first bulb after selection is put back in the box before making the second selection. The probability that both the bulbs are without defect is

$A$ and $B$ are two independent events such that $P(A) = \frac{1}{2}$ and $P(B) = \frac{1}{3}$. Then $P$ (neither $A$ nor $B$) is equal to

$A$ basket contains $5$ apples and $7$ oranges and another basket contains $4$ apples and $8$ oranges. If one fruit is picked out at random from each basket,then the probability of getting one apple and one orange is

$A$ bag $B$ contains $4$ white balls and $2$ black balls. Another bag $C$ contains $3$ white balls and $5$ black balls. If one ball is drawn randomly from each bag, then the probability that the two balls drawn are both white is

When a missile is fired from a ship,the probability that it is intercepted is $\frac{1}{3}$ and the probability that the missile hits the target,given that it is not intercepted,is $\frac{3}{4}$. If three missiles are fired independently from the ship,then the probability that all three hit the target is: