If $3 \sin \theta = 2 \sin 3 \theta$ and $0 < \theta < \pi$,then $\sin \theta =$

  • A
    $\frac{\sqrt{2}}{\sqrt{5}}$
  • B
    $\frac{\sqrt{3}}{2 \sqrt{2}}$
  • C
    $\frac{\sqrt{2}}{3}$
  • D
    $\frac{\sqrt{3}}{\sqrt{5}}$

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