જો $\frac{\sin (A+B)}{\sin (A-B)}=\frac{\cos (C+D)}{\cos (C-D)}$ હોય,તો $\tan A \cot B=$

  • A
    $\cot C \cot D$
  • B
    $-\tan C \tan D$
  • C
    $\tan C \tan D$
  • D
    $-\cot C \cot D$

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