यदि $\frac{1-\tan \theta}{1+\tan \theta}=\frac{1}{\sqrt{3}}$,जहाँ $\theta \in \left(0, \frac{\pi}{2}\right)$,तो $\theta=$

  • A
    $\frac{\pi}{12}$
  • B
    $\frac{\pi}{4}$
  • C
    $\frac{\pi}{6}$
  • D
    $\frac{\pi}{3}$

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