If $\overline{p}=2 \hat{i}+\hat{k}$,$\overline{q}=\hat{i}+\hat{j}+\hat{k}$,$\overline{r}=4 \hat{i}-3 \hat{j}+7 \hat{k}$ and a vector $\overline{m}$ is such that $\overline{m} \times \overline{q}=\overline{r} \times \overline{q}$ and $\overline{m} \cdot \overline{p}=0$,then $\overline{m} = \dots$

  • A
    $\hat{i}-8 \hat{j}-2 \hat{k}$
  • B
    $-10 \hat{i}+3 \hat{j}+7 \hat{k}$
  • C
    $-\hat{i}-8 \hat{j}+2 \hat{k}$
  • D
    $2 \hat{i}+4 \hat{j}+\hat{k}$

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If $\overrightarrow{a} \cdot \hat{i} = \overrightarrow{a} \cdot (2 \hat{i} + \hat{j}) = \overrightarrow{a} \cdot (\hat{i} + \hat{j} + 3 \hat{k}) = 1$,then $\overrightarrow{a}$ is equal to :

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