If $\overline{a}=2 \hat{i}+2 \hat{j}+3 \hat{k}$,$\overline{b}=-\hat{i}+2 \hat{j}+\hat{k}$ and $\overline{c}=3 \hat{i}+\hat{j}$ such that $\overline{b}+\lambda \overline{a}$ is perpendicular to $\overline{c}$,then $\lambda$ is

  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{6}$
  • D
    $\frac{1}{8}$

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