If $\overrightarrow{a} \cdot \hat{i}=4$,then $(\overrightarrow{a} \times \hat{j}) \cdot(2 \hat{j}-3 \hat{k})$ is equal to

  • A
    $12$
  • B
    $2$
  • C
    $0$
  • D
    $-12$

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