If A = begin{bmatrix} i & 0 0 & -i end{bmatr | vedclass

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(B) Given $A = \begin{bmatrix} i & 0 \ 0 & -i \end{bmatrix}$ and $B = \begin{bmatrix} 0 & i \ i & 0 \end{bmatrix}$.First,calculate $A^2$:$A^2 = \beg

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$A^2 = B^2$

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(B) Given $A = \begin{bmatrix} i & 0 \ 0 & -i \end{bmatrix}$ and $B = \begin{bmatrix} 0 & i \ i & 0 \end{bmatrix}$.First,calculate $A^2$:$A^2 = \begin{bmatrix} i & 0 \ 0 & -i \end{bmatrix} \begin{bmatrix} i & 0 \ 0 & -i \end{bmatrix} = \begin{bmatrix} i^2 & 0 \ 0 & (-i)^2 \end{bmatrix} = \begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix} = -I$.Next,calculate $B^2$:$B^2 = \begin{bmatrix} 0 & i \ i & 0 \end{bmatrix} \begin{bmatrix} 0 & i \ i & 0 \end{bmatrix} = \begin{bmatrix} i^2 & 0 \ 0 & i^2 \end{bmatrix} = \begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix} = -I$.Since $A^2 = \begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix}$ and $B^2 = \begin{bmatrix} -1 & 0 \ 0 & -1 \end{bmatrix}$,we observe that $A^2 = B^2$.

If $A = \begin{bmatrix} i & 0 \\ 0 & -i \end{bmatrix}$ and $B = \begin{bmatrix} 0 & i \\ i & 0 \end{bmatrix}$,where $i = \sqrt{-1}$,then which of the following relations is correct?

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