If alpha is the coefficient of performance of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The coefficient of performance $\alpha$ of a refrigerator is defined as the ratio of heat extracted from the cold reservoir $(Q_2)$ to the work do

Vedclass · Accepted Answer

$\frac{\alpha Q_1}{1+\alpha}$

Vedclass · Answer

(C) The coefficient of performance $\alpha$ of a refrigerator is defined as the ratio of heat extracted from the cold reservoir $(Q_2)$ to the work done $(W)$ on the system: $\alpha = \frac{Q_2}{W}$.Since $W = Q_1 - Q_2$,where $Q_1$ is the heat released to the hot reservoir,we have $\alpha = \frac{Q_2}{Q_1 - Q_2}$.Cross-multiplying gives: $\alpha(Q_1 - Q_2) = Q_2$.Expanding the equation: $\alpha Q_1 - \alpha Q_2 = Q_2$.Rearranging to solve for $Q_2$: $\alpha Q_1 = Q_2 + \alpha Q_2 = Q_2(1 + \alpha)$.Therefore,$Q_2 = \frac{\alpha Q_1}{1 + \alpha}$.

If $\alpha$ is the coefficient of performance of a refrigerator and $Q_1$ is the heat released to the hot reservoir,then the heat extracted from the cold reservoir $Q_2$ is

Similar Questions

If the door of a refrigerator is kept open,then which of the following is true?

$A$ refrigerator is to maintain eatables kept inside at $9^{\circ} C$. If room temperature is $36^{\circ} C$,calculate the coefficient of performance.

Can the coefficient of performance of a refrigerator be increased by increasing the mass of the working substance?

$A$ Carnot engine,having an efficiency of $\eta = 1/10$ as a heat engine,is used as a refrigerator. If the work done on the system is $10 \ J$,the amount of energy absorbed from the reservoir at a lower temperature is ....... $J$.

By opening the door of a refrigerator placed inside a room,you:

Vedclass Test Series

Exam Paper Generator

Online Exam Module