If text{cosec } A + cot A = frac{11}{2}, then | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We know that $	ext{cosec}^2 A - \cot^2 A = 1.$Using the identity $a^2 - b^2 = (a - b)(a + b),$ we have $(	ext{cosec } A - \cot A)(	ext{cosec }

Vedclass · Accepted Answer

$\frac{44}{117}$

Vedclass · Answer

(C) We know that $	ext{cosec}^2 A - \cot^2 A = 1.$Using the identity $a^2 - b^2 = (a - b)(a + b),$ we have $(	ext{cosec } A - \cot A)(	ext{cosec } A + \cot A) = 1.$Given $	ext{cosec } A + \cot A = \frac{11}{2},$ we substitute this into the identity:$(	ext{cosec } A - \cot A) 	imes \frac{11}{2} = 1 \Rightarrow 	ext{cosec } A - \cot A = \frac{2}{11}.$Now,subtract the two equations:$(	ext{cosec } A + \cot A) - (	ext{cosec } A - \cot A) = \frac{11}{2} - \frac{2}{11}.$$2 \cot A = \frac{121 - 4}{22} = \frac{117}{22}.$$\cot A = \frac{117}{44}.$Since $	an A = \frac{1}{\cot A},$ we get $	an A = \frac{44}{117}.$

If $\text{cosec } A + \cot A = \frac{11}{2},$ then $\tan A = $

Similar Questions

The number of solutions of the equation $32^{\tan^{2} x} + 32^{\sec^{2} x} = 81$ for $0 \leq x \leq \frac{\pi}{4}$ is:

The extreme values of $4 \cos \left(x^2\right) \cos \left(\frac{\pi}{3}+x^2\right) \cos \left(\frac{\pi}{3}-x^2\right)$ over $\mathbb{R}$ are

The exact value of $\cos^2 73^\circ + \cos^2 47^\circ + (\cos 73^\circ \cdot \cos 47^\circ)$ is

If $\sec \theta + \tan \theta = \frac{1}{3}$,then the quadrant in which $2 \theta$ lies is

If $P = \tan 15^{\circ} + \cot 15^{\circ}$,$Q = \tan 22 \frac{1}{2}^{\circ} + \cot 22 \frac{1}{2}^{\circ}$ and $R = \sin 54^{\circ} + \sin 18^{\circ}$,then their ascending order is

Vedclass Test Series

Exam Paper Generator

Online Exam Module