If $f(x) = \frac{1+x}{1-x}$ where $x \neq 1$,then $f(x) \cdot f(y) = $ . . . . . . .

  • A
    $f\left(\frac{x+y}{1-xy}\right)$
  • B
    $f\left(\frac{x+y}{1+xy}\right)$
  • C
    $f(x) \cdot f(y)$
  • D
    $f\left(\frac{1}{1+xy}\right)$

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