If A is a 2 times 2 matrix and a_{ij} = frac{ | vedclass

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(A) For a $2 	imes 2$ matrix $A = [a_{ij}]$,the elements are given by $a_{ij} = \frac{i + 2j^2}{3}$.For $i=1, j=1$: $a_{11} = \frac{1 + 2(1)^2}{3} =

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$\left[\begin{array}{cc} 1 & 3 \ \frac{4}{3} & \frac{10}{3} \end{array}ight]$

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(A) For a $2 	imes 2$ matrix $A = [a_{ij}]$,the elements are given by $a_{ij} = \frac{i + 2j^2}{3}$.For $i=1, j=1$: $a_{11} = \frac{1 + 2(1)^2}{3} = \frac{1 + 2}{3} = \frac{3}{3} = 1$.For $i=1, j=2$: $a_{12} = \frac{1 + 2(2)^2}{3} = \frac{1 + 8}{3} = \frac{9}{3} = 3$.For $i=2, j=1$: $a_{21} = \frac{2 + 2(1)^2}{3} = \frac{2 + 2}{3} = \frac{4}{3}$.For $i=2, j=2$: $a_{22} = \frac{2 + 2(2)^2}{3} = \frac{2 + 8}{3} = \frac{10}{3}$.Thus,the matrix $A = \left[\begin{array}{cc} 1 & 3 \ \frac{4}{3} & \frac{10}{3} \end{array}ight]$.

Market	$x$	$y$	$z$
$I$	$10,000$	$2,000$	$18,000$
$II$	$6,000$	$20,000$	$8,000$

If $A$ is a $2 \times 2$ matrix and $a_{ij} = \frac{i + 2j^2}{3}$,then find the matrix $A = [a_{ij}]_{2 \times 2}$.

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