જો $\sin \alpha = \frac{-3}{5}$ જ્યાં $\pi < \alpha < \frac{3\pi}{2}$ હોય,તો $\cos \frac{\alpha}{2} = $

  • A
    $\frac{-1}{\sqrt{10}}$
  • B
    $\frac{1}{\sqrt{10}}$
  • C
    $\frac{3}{\sqrt{10}}$
  • D
    $\frac{-3}{\sqrt{10}}$

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