If 1 mole of a solute dissociates to give n n | vedclass

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(C) For a solute dissociating as $A \rightarrow nB$,the initial moles are $1$ and $0$ respectively.After dissociation,the moles are $(1-\alpha)$ and $

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$\frac{i-1}{n-1}$

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(C) For a solute dissociating as $A \rightarrow nB$,the initial moles are $1$ and $0$ respectively.After dissociation,the moles are $(1-\alpha)$ and $n\alpha$.The total number of moles at equilibrium is $(1-\alpha + n\alpha) = 1 + \alpha(n-1)$.The van't Hoff factor $i$ is defined as the ratio of observed moles to initial moles: $i = \frac{1 + \alpha(n-1)}{1}$.Rearranging for $\alpha$: $i - 1 = \alpha(n-1)$.Therefore,$\alpha = \frac{i-1}{n-1}$.

If $1$ mole of a solute dissociates to give $n$ number of ions,then the degree of dissociation $\alpha$ in terms of the van't Hoff factor $i$ is given by:

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