If $\sin A = n \sin B,$ then $\frac{n - 1}{n + 1} \tan \frac{A + B}{2} = $

  • A
    $\sin \frac{A - B}{2}$
  • B
    $\tan \frac{A - B}{2}$
  • C
    $\cot \frac{A - B}{2}$
  • D
    None of these

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