If |x+5| geq 10,then: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given the inequality $|x+5| \geq 10$. By the property of absolute value inequalities,$|u| \geq a$ implies $u \leq -a$ or $u \geq a$. Therefore,$x+

Vedclass · Accepted Answer

$x \in (-\infty, -15] \cup [5, \infty)$

Vedclass · Answer

(C) Given the inequality $|x+5| \geq 10$. By the property of absolute value inequalities,$|u| \geq a$ implies $u \leq -a$ or $u \geq a$. Therefore,$x+5 \leq -10$ or $x+5 \geq 10$. Solving the first part: $x \leq -10 - 5 \Rightarrow x \leq -15$. Solving the second part: $x \geq 10 - 5 \Rightarrow x \geq 5$. Combining these,we get $x \in (-\infty, -15] \cup [5, \infty)$.

If $|x+5| \geq 10$,then:

Similar Questions

Solve the following inequality and represent it on a number line: $\frac{x-1}{2}+5 \geq \frac{2x-1}{3}+15$

The inequality represented on the number line is:

Solve the following system of linear inequalities and represent the solution graphically on a number line:
$3x - 7 > 2(x - 6), 6 - x > 11 - 2x$

Solve for $x$ in the following inequality: $-5 \leq \frac{2-3x}{4} \leq 9$

Solve the inequality $x + 2 < -8$ for the following cases: $(1) x \in N$,$(2) x \in Z$,$(3) x \in R$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module