(B) Given $B = A + C$. Taking tangent on both sides,$\tan B = \tan (A + C)$. Using the formula $\tan (A + C) = \frac{\tan A + \tan C}{1 - \tan A \tan

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(B) Given $B = A + C$. Taking tangent on both sides,$\tan B = \tan (A + C)$. Using the formula $\tan (A + C) = \frac{\tan A + \tan C}{1 - \tan A \tan C}$,we get: $\tan B = \frac{\tan A + \tan C}{1 - \tan A \tan C}$. Cross-multiplying gives: $\tan B (1 - \tan A \tan C) = \tan A + \tan C$. $\tan B - \tan A \tan B \tan C = \tan A + \tan C$. Rearranging the terms,we get: $\tan A \tan B \tan C = \tan B - \tan A - \tan C$.