If A is a 3 times 3 matrix such that |5 times | vedclass

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(C) Given that $A$ is a $3 	imes 3$ matrix,so $n = 3$. We know that for any $n 	imes n$ matrix $M$,$|kM| = k^n |M|$. Applying this to $|5 	imes 	e

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$\pm 1/5$

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(C) Given that $A$ is a $3 	imes 3$ matrix,so $n = 3$. We know that for any $n 	imes n$ matrix $M$,$|kM| = k^n |M|$. Applying this to $|5 	imes 	ext{adj}(A)| = 5$,we get $5^3 |	ext{adj}(A)| = 5$. This simplifies to $|	ext{adj}(A)| = \frac{5}{5^3} = \frac{1}{5^2} = \frac{1}{25}$. We also know the property $|	ext{adj}(A)| = |A|^{n-1}$. For $n = 3$,$|	ext{adj}(A)| = |A|^{3-1} = |A|^2$. Equating the two expressions for $|	ext{adj}(A)|$,we have $|A|^2 = \frac{1}{25}$. Taking the square root on both sides,we get $|A| = \pm \frac{1}{5}$.

If $A$ is a $3 \times 3$ matrix such that $|5 \times \text{adj} A|=5$,then $|A|$ is equal to

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