If $f(x) = \begin{cases} \frac{\log_{e} x}{x-1} & x \neq 1 \\ k & x=1 \end{cases}$ is continuous at $x=1$,then the value of $k$ is

  • A
    $1$
  • B
    $e$
  • C
    $-1$
  • D
    $0$

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