If 4sin^{-1}x + cos^{-1}x = pi,then x is equa | vedclass

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(B) We are given the equation $4\sin^{-1}x + \cos^{-1}x = \pi$. We know the identity $\sin^{-1}x + \cos^{-1}x = \frac{\pi}{2}$. We can rewrite the giv

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$\frac{1}{2}$

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(B) We are given the equation $4\sin^{-1}x + \cos^{-1}x = \pi$. We know the identity $\sin^{-1}x + \cos^{-1}x = \frac{\pi}{2}$. We can rewrite the given equation as $3\sin^{-1}x + (\sin^{-1}x + \cos^{-1}x) = \pi$. Substituting the identity,we get $3\sin^{-1}x + \frac{\pi}{2} = \pi$. Subtracting $\frac{\pi}{2}$ from both sides,we get $3\sin^{-1}x = \frac{\pi}{2}$. Dividing by $3$,we get $\sin^{-1}x = \frac{\pi}{6}$. Taking the sine of both sides,we find $x = \sin\left(\frac{\pi}{6}\right) = \frac{1}{2}$.

If $4\sin^{-1}x + \cos^{-1}x = \pi$,then $x$ is equal to

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