If $\overrightarrow{F}=(4 \hat{i}-10 \hat{j}) \text{ N}$ and $\overrightarrow{r}=(-5 \hat{i}-3 \hat{j}) \text{ m}$,then $(\overrightarrow{r} \times \overrightarrow{F})$ is

  • A
    $(-20 \hat{i}+3 \hat{j}) \text{ Nm}$
  • B
    $62 \hat{k} \text{ Nm}$
  • C
    $10 \sqrt{13} \text{ Nm}$
  • D
    $38 \text{ Nm}$

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